Physics Problems With Solutions Mechanics For Olympiads And Contests | 2026 |

Kinetic energy (KE) = (⁄ 2 )mv² = (⁄ 2 )(0.5)(14.14)² = 50 J

a = F cos 30° / m = 10 * (√3/2) / 2 = 4.33 m/s²

Potential energy (PE) = mgh = 0.5(10)(10) = 50 J Kinetic energy (KE) = (⁄ 2 )mv² = (⁄ 2 )(0

Using the equation: v = v₀ + at, we get: v = 10 + 2(5) = 20 m/s

A ball of mass 0.5 kg is thrown vertically upwards with an initial velocity of 20 m/s. Find its kinetic energy and potential energy at a height of 10 m. Given: Mass (m) = 0

Given: Initial velocity (v₀) = 10 m/s, acceleration (a) = 2 m/s², time (t) = 5 s.

Given: Mass (m) = 0.5 kg, initial velocity (v₀) = 20 m/s, height (h) = 10 m. Find its final velocity and position

A particle moves along a straight line with an initial velocity of 10 m/s. It accelerates uniformly at 2 m/s² for 5 seconds. Find its final velocity and position.