A snail is at the bottom of a 20-foot well. Each day, it climbs up 3 feet, but at night, it slips back 2 feet. How many days will it take for the snail to reach the top of the well? The snail climbs 3 feet up and slips 2 feet back each day, making a net progress of 1 foot per day. Step 2: Calculate the Progress Since the well is 20 feet deep, we need to calculate how many days it will take for the snail to climb 17 feet (20 - 3 = 17), because on the 18th foot, it will reach the top and won’t slip back. 3: Solve for Days It takes 17 days for the snail to climb 17 feet. On the 18th day, when it climbs 3 feet, it will reach 20 feet and exit the well.
The answer is 18 .
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